Use knowledge and formulas in numerical/situational problems
compute, determine, solve
Q15–Q20
How to use: select your answer for each question (optional), then click Show Answer & Explanation.
Mark yourself Correct / Wrong using the buttons that appear — your score is tracked in the bar below.
All answers include full explanations; numerical questions include the worked solution.
Recall of definitions, facts, and terminology. Choose the answer, then reveal.
1A telecommunication switching system primarily exists in a network to:Remember
a) Amplify signals on long-distance links
b) Interconnect transmission paths so that any subscriber can communicate with any other
c) Convert analog signals to digital form
d) Compress signals to save bandwidth
Answer: (b). The fundamental purpose of switching is resource sharing: a limited pool of trunks and switch paths is shared among many subscribers, avoiding the N(N−1)/2 dedicated links a fully connected network would need.
2The first commercial automatic telephone exchange (step-by-step, Strowger) entered service in:Remember
a) 1876
b) 1878
c) 1892
d) 1938
Answer: (c) 1892. Almon Brown Strowger patented the automatic exchange in 1891; the first commercial installation was at La Porte, Indiana, in 1892. (1878 was the first manual exchange; 1938 the crossbar era.)
3In a step-by-step exchange, the equipment that responds to the caller's off-hook condition and finds a free first selector is the:Remember
a) Connector
b) Marker
c) Line finder
d) Register
Answer: (c) Line finder. On off-hook, the line finder (or preselector) hunts for the calling line and seizes a free first selector, after which dial tone is returned. The connector (final selector) is the last stage; the marker and register are crossbar/common-control elements.
4In a crossbar switch, a crosspoint at the intersection of a horizontal bar and a vertical bar is closed by:Remember
a) A rotating wiper driven by dial pulses
b) Energizing one horizontal and one vertical electromagnetic bar simultaneously
c) A time-slot assignment in the control memory
d) A reed relay operated by the called party's answer
Answer: (b). A crossbar crosspoint is a mechanically latched contact operated by two electromagnets: the horizontal bar selects the inlet and the vertical bar the outlet; energizing one of each closes the crosspoint at their intersection. It remains latched for the call duration.
5One Erlang of telephone traffic corresponds to:Remember
a) One call per hour
b) One circuit occupied continuously (100% of the time)
c) One hundred call-seconds per hour
d) One conversation of three minutes' duration
Answer: (b). The Erlang is a dimensionless unit: 1 E = one circuit busy for the whole observation period = 1 call-hour per hour = 36 CCS (cent-call-seconds). It measures average simultaneous circuit occupancy, not a count of calls.
6The switching function in which many input lines are served by fewer output paths (e.g. 128 lines → 16 trunks) is called:Remember
a) Expansion
b) Concentration
c) Distribution
d) Multiplexing
Answer: (b) Concentration. Concentration reflects that only a small fraction of subscribers originate calls simultaneously, so a large line pool can share a smaller trunk pool. Distribution has equal inlets/outlets; expansion is the reverse (few in, many out).
7The grade of service (GoS) of a loss (blocking) system is specified as:Remember
a) The average call holding time
b) The number of trunks in the group
c) The probability that an arriving call finds all servers busy and is lost
d) The call setup time in seconds
Answer: (c). GoS is the blocking probability B — the fraction of offered calls that cannot be served immediately and are cleared (lost-calls-cleared assumption, as in the Erlang B model). Typical design targets: 0.1%–2%.
Part B — Level 2: Understand (Q8–Q14)
Explanation, comparison, and interpretation of concepts.
8Why does a fully interconnected network of 10,000 subscribers become impractical, and how does switching solve the problem?Understand
a) It needs 10,000 switches, which is too expensive
b) It requires 10,000 × 9,999 / 2 ≈ 50 million dedicated links; a switch shares a small pool of trunks among all users
c) Crosstalk between 10,000 pairs makes reception impossible
d) Subscribers could not be billed without a switch
Answer: (b). Every pair of subscribers needs its own link: N(N−1)/2 ≈ 5×107 lines for N = 10,000 — each used a tiny fraction of the time. A switch exploits the low simultaneous-usage factor, so a few thousand trunks serve the whole population at an acceptable blocking probability.
9The principal disadvantage of step-by-step (direct control) compared with crossbar (common control) is:Understand
a) It cannot interconnect two analog subscribers
b) Dial pulses drive the switch stage-by-stage directly, making setup slow and tying up equipment inefficiently, with no flexible routing
c) It requires N² crosspoints for N subscribers
d) It needs a digital processor to decode digits
Answer: (b). In SxS the subscriber's dial pulses operate the selectors directly, stage by stage: setup is slow (10 pps), control equipment is dedicated for the entire call, and routing is rigid. Crossbar's marker (common control) decodes digits centrally, selects any free path quickly, and is released after setup.
10In time-division switching, the function of the control store in a time-slot interchange (TSI) is to:Understand
a) Buffer the actual speech samples between inlet and outlet
b) Hold the inlet-to-outlet time-slot map written by the call processor at setup
c) Amplify the samples to compensate bus loss
d) Count the number of active calls for billing
Answer: (b). The speech store buffers the samples; the control store is written once per call by the processor and thereafter dictates, slot by slot, which speech-store location is read onto each outlet — i.e., it realizes the permutation of time slots.
11Why is a single-stage N×N space switch with N² crosspoints considered wasteful, and what is the standard remedy?Understand
a) Crosspoints wear out after N operations, so more are needed as spares
b) At most N crosspoints (typically far fewer) can be active at once, so utilization ≤ 1/N; multi-stage (Clos-type) networks reduce the count toward O(N log N)
c) Each crosspoint can carry only one frequency, limiting capacity
d) The matrix must be duplicated for two-wire to four-wire conversion
Answer: (b). With at most N simultaneous connections, at most N of the N² crosspoints are ever closed simultaneously (and usually much fewer), giving utilization ≤ 1/N. Multi-stage networks with internal links (e.g. three-stage Clos) achieve huge crosspoint savings at the cost of a small, engineered probability of internal blocking.
12Blocking in a circuit-switched telephone network means:Understand
a) A call is completed but with degraded voice quality
b) An arriving call finds no free circuit/path and cannot be served (it is lost or must retry)
c) Two calls share one physical wire simultaneously
d) The exchange software halts all processing
Answer: (b). A blocking system has finite servers; when all are occupied, a new arrival is refused (lost-calls-cleared) under the Erlang B model. Blocking probability is the GoS. It is a deliberate trade-off: providing enough capacity for zero blocking would be uneconomical.
13Which statement correctly contrasts space-division and time-division switching?Understand
a) Space division gives each connection a separate physical path for the whole call; time division shares one path, separating conversations into distinct time slots
b) Space division is only possible for digital signals; time division only for analog
c) Time division requires one physical wire per simultaneous conversation
d) Space division needs no crosspoints, whereas time division needs N² of them
Answer: (a). Space division = separate paths in space (crosspoints/wipers); time division = one shared bus where samples are interleaved in time and the switch permutes slot assignments (TSI). Time division dramatically reduces physical hardware per conversation — the key idea behind PCM digital exchanges.
14In a step-by-step exchange, if a subscriber dials the digit "5", the selector wiper first:Understand
a) Rotates five times horizontally and then rises
b) Rises vertically to level 5 in response to the five dial pulses, then auto-hunts (rotates) to a free outlet at that level
c) Connects directly to connector number 5
d) Sends the digit to the marker for path selection
Answer: (b). Each dial pulse (10 pps) steps the wiper up one level; after five pulses it is at level 5. The wiper then rotates automatically ("hunts") until it finds a free outlet on that level, connecting to the next selector stage. Digit translation by a marker belongs to common-control systems, not SxS.
Part C — Level 3: Apply (Q15–Q20)
Numerical and situational application of the concepts and formulas.
15A fully connected network is planned for 50 subscribers. How many dedicated two-way links are required?Apply
a) 50
b) 1,225
c) 2,450
d) 100
Answer: (b) 1,225.
Links = N(N − 1)/2 = 50 × 49 / 2 = 1,225
Each subscriber needs a dedicated link to every other subscriber. This quadratic growth is precisely why even modest networks use switched (shared-trunk) architectures.
16A concentrator serves 120 subscriber lines through 12 trunks. If the busy-hour simultaneous-usage factor is 0.15, the offered traffic carried by the trunks is approximately:Apply
a) 120 Erlangs
b) 12 Erlangs
c) 18 Erlangs
d) 1.8 Erlangs
Answer: (c) 18 Erlangs.
A = (lines) × (usage factor) = 120 × 0.15 = 18 E
Equivalently A = λh. Note the offered traffic (18 E) exceeds the number of trunks (12), so this group would block heavily — in practice the usage factor must be lower or more trunks provided (see Q17/Q18).
17During the busy hour, an exchange records 360 calls with a mean holding time of 100 s. The offered traffic is:Apply
a) 3,600 Erlangs
b) 36 Erlangs
c) 10 Erlangs
d) 1 Erlang
Answer: (c) 10 Erlangs.
A = C · T / 3600 = 360 × 100 / 3600 = 10 E
Total traffic carried in the hour is 360 × 100 = 36,000 call-seconds = 36,000/3,600 = 10 call-hours, i.e. 10 Erlangs.
18Using the Erlang B model, the number of trunks required to carry 4 Erlangs of offered traffic at a 1% grade of service is:Apply
From Erlang B tables/recursion Bk = A·Bk−1/(k + A·Bk−1): eight trunks give about 3% blocking (poor), nine trunks give about 0.9%, meeting the 1% target. Utilization = 4(1−0.009)/9 ≈ 44%.
19A group of 20 servers carries 14 Erlangs with a measured blocking of 0.7%. The carried traffic and the per-server utilization are, respectively:Apply
Offered traffic is reduced by the blocked fraction to give carried traffic; dividing by the number of servers gives the occupancy per server.
20A small exchange is built as a single-stage 8×8 crossbar matrix. Six calls are already set up on the pairs (In0→Out1), (In1→Out3), (In2→Out0), (In3→Out5), (In4→Out2), (In6→Out7). A new request arrives for In5 → Out4. The outcome is:Apply
a) The call is set up on crosspoint (5,4) immediately
b) The call blocks because 6 of 64 crosspoints are already in use
c) The call blocks only if input 5 or output 4 is already engaged; here neither is used, so the call is established
d) The marker must first convert the two-wire line to four-wire
Answer: (c). In a single-stage matrix, a call blocks when its own inlet or outlet is already busy (a non-blocking requirement per inlet/outlet), because one inlet can feed only one output and vice versa. Here inputs 0–4, 6 and outputs 0,1,2,3,5,7 are busy; input 5 and output 4 are both free, so crosspoint (5,4) closes and the call proceeds. Blocking arises for, say, In0 → Out4, since In0 is already engaged. (Multi-stage internal blocking is a separate phenomenon.)
Post-Test Results & Interpretation
Your live score is shown in the sticky bar at the top of the quiz. Interpretation guide:
Proceed to higher-order tasks: analysis of multi-stage networks (Clos), design projects
70–89%
Good grasp of concepts; some application gaps
Re-work the numerical questions (Q15–Q20) and Erlang B table use
50–69%
Partial understanding
Re-study the step-by-step and crossbar operation sections; re-attempt the interactive matrix simulation
< 50%
Significant gaps
Re-read the full study guide before re-attempting; focus on switching functions, control types, and traffic units
Note for the instructor: All items map to Bloom's levels 1–3 only (Remember: Q1–Q7; Understand: Q8–Q14;
Apply: Q15–Q20). Items may be used for diagnostic pre/post-testing; suggested pass mark 70%.