This quiz tests your understanding of decibel calculations relevant to electrical and communication engineering. Select the best answer for each question.
| Change in Intensity | Change in Intensity Level |
|---|---|
| Multiply/divide by two | Add/subtract 3 dB |
| Multiply/divide by ten | Add/subtract 10 dB |
Question 1: b) 3 dB
According to decibel rules of thumb, doubling the intensity (from I to 2I) increases the sound intensity level by 3 dB:cite[10]. This is a fundamental relationship in acoustic measurements.
Question 2: b) 10 dB
When sound intensity increases by a factor of 10, the sound intensity level increases by 10 dB:cite[10]. This logarithmic relationship is why decibels are useful for representing large ratios compactly.
Question 3: b) 83 dB
When two identical sounds combine, their intensities add. Doubling the intensity increases the sound level by 3 dB:cite[10]. Therefore, two 80 dB sources produce 83 dB, not 160 dB, because decibels are logarithmic units, not linear.
Question 4: c) 1000
To increase from 80 dB to 110 dB requires a 30 dB increase. Each 10 dB increase requires multiplying intensity by 10. Therefore, 30 dB requires 10 × 10 × 10 = 1000 times the intensity:cite[10]. Since intensities add, we need 1000 sources.
Question 5: a) 30 dB
For power ratios, dB = 10 × log₁₀(P₂/P₁). A ratio of 1000:1 gives 10 × log₁₀(1000) = 10 × 3 = 30 dB. This formula is essential for electrical engineering power calculations.
Question 6: b) 20 dB
For voltage ratios (assuming same impedance), dB = 20 × log₁₀(V₂/V₁). A ratio of 10:1 gives 20 × log₁₀(10) = 20 × 1 = 20 dB. Note the different multiplier (20) for voltage/pressure vs. power/intensity (10).
Question 7: a) 10 times more intense
A 10 dB increase corresponds to a 10-fold increase in intensity:cite[10]. Normal breathing at 10 dB is barely audible and is used as a reference for almost inaudible sounds:cite[1].
Question 8: c) 90 dB
If a sound is 1000 times more intense, this represents three factors of 10 (10 × 10 × 10). Each factor of 10 adds 10 dB, so 3 × 10 dB = 30 dB increase. Adding 30 dB to 60 dB gives 90 dB:cite[10].
Question 9: d) 10 W
SNR = 10 × log₁₀(Psignal/Pnoise) = 40 dB. Therefore, log₁₀(Psignal/Pnoise) = 4, so Psignal/Pnoise = 10⁴ = 10,000. With Pnoise = 1 mW, Psignal = 10,000 mW = 10 W.
Question 10: c) Normal breathing
According to common sound level charts, normal breathing produces sound at approximately 10 dB:cite[1]. This represents an almost inaudible sound level that serves as a good reference point for the lowest end of the audible range.